what is the order of source operands in AT&T syntax compared to Intel syntax?

The Intel ISA reference documentation for this instruction is clear:

VPBLENDVB xmm1, xmm2, xmm3/m128, xmm4

>Select byte values from `xmm2` and `xmm3/m128` using mask bits in the specified mask register, `xmm4`, and store the values into `xmm1`.

>`xmm1` is the destination, `xmm2/3/4` are source operands

So what does this become using AT&T syntax? We know that the destination register must be last, but what is the order of source operands?

vpblendvb $xmm2, $xmm3, $xmm4, $xmm1

or

vpblendvb $xmm4, $xmm3, $xmm2, $xmm1

or something else?

Assembling (note GAS uses `%` instead of `$` to denote registers) the following:

vpblendvb %xmm4, %xmm3, %xmm2, %xmm1

with the GNU assembler (version 2.21.0.20110327 on x86_64 2.6.38 linux) and then disassembling yields:

$ objdump -d a.out
0: c4 e3 69 4c cb 40 vpblendvb %xmm4,%xmm3,%xmm2,%xmm1

in intel syntax (as the manual shows):


$ objdump -d -M intel a.out
0: c4 e3 69 4c cb 40 vpblendvb xmm1,xmm2,xmm3,xmm4

So it looks like the order of all the arguments is reversed.