Write a number with two decimal places SQL Server

How do you write a number with two decimal places for sql server?

Multiply the value you want to insert (ex. 2.99) by 100

Then insert the division by 100 of the result adding .01 to the end:

299.01/100

This will allow total 10 digits with 2 values after the decimal. It means that it can accomodate the value value before decimal upto 8 digits and 2 after decimal.

To validate, put the value in the following query.

DECLARE vtest number(10,2);
BEGIN
SELECT 10.008 INTO vtest FROM dual;
dbms_output.put_line(vtest);
END;

Use `Str()` Function. It takes three arguments(the number, the number total characters to display, and the number of decimal places to display



Select Str(12345.6789, 12, 3)

displays: ' 12345.679' ( 3 spaces, 5 digits 12345, a decimal point, and three decimal digits (679). - it rounds if it has to truncate, (unless the integer part is too large for the total size, in which case asterisks are displayed instead.)

for a Total of 12 characters, with 3 to the right of decimal point.

Generally you can define the precision of a number in SQL by defining it with parameters. For most cases this will be `NUMERIC(10,2)` or `Decimal(10,2)` - will define a column as a Number with 10 total digits with a precision of 2 (decimal places).

*Edited for clarity*

If you're fine with **rounding** the number instead of truncating it, then it's just:

ROUND(column_name,decimals)

This work for me and always keeps two digits fractions

23.1 ==> 23.10

25.569 ==> 25.56

1 ==> 1.00

Cast(CONVERT(DECIMAL(10,2),Value1) as nvarchar) AS Value2

[Code screenshot][1]


[1]:

If you only need two decimal places, simplest way is..


SELECT CAST(12 AS DECIMAL(16,2))

OR

SELECT CAST('12' AS DECIMAL(16,2))

*Output*

12.00

Try this:



declare @MyFloatVal float;

set @MyFloatVal=(select convert(decimal(10, 2), 10.254000))

select @MyFloatVal

Convert(decimal(18,2),r.AdditionAmount) as AdditionAmount

This is how the kids are doing it today:

DECLARE @test DECIMAL(18,6) = 123.456789
SELECT FORMAT(@test, '##.##')

123.46